( ) ADVANCED HONORS CHEMISTRY - CHAPTER 14 NAME: THE BEHAVIOR OF GASES GRAHAM'S LAW WORKSHEET - ANSWERS - V8 PAGE:

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1 ADVANCED HONORS CHEMISTRY - CHAPTER 14 NAME: THE BEHAVIOR OF GASES DATE: GRAHAM'S LAW WORKSHEET - ANSWERS - V8 PAGE: 1. How fast would a ecule of sulfur dioxide travel if an atom of krypton (aarrgghh!) travels an average of 750 m/s at 200. o C Name Sulfur Dioxide Krypton Formula SO 2 Kr 64 g Velocity m 84 g 750 m Velocity Sulfur Dioxide Velocity Krypton Krypton Sulfur Dioxide ( Velocity Krypton ) Velocity Sulfur Dioxide Velocity Velocity Krypton Krypton Krypton Sulfur Dioxide Velocity Sulfur Dioxide ( Velocity Krypton )( Krypton ) Sulfur Dioxide Velocity Sulfur Dioxide 750 m 64 g 84 g Velocity Sulfur Dioxide meters

2 2. A fluorine gas ecule travels at about 300. m/s at room temperature. How fast would a ecule of methanol, CH 3 OH, travel at the same temperature Name Fluorine Methanol Formula F 2 CH 3 OH Velocity 38.0 g 300. m 32.0 g m Velocity Fluorine Velocity Methanol Methanol Fluorine Cross Multiply To Get The Variable in the Numerator. ( Velocity Fluorine )( Fluorine ) ( Velocity Methanol )( Methanol ) Methanol ( Velocity Fluorine ) Fluorine Velocity Methanol ( Velocity Methanol )( Methanol ) Methanol ( Velocity Fluorine )( Fluorine ) Methanol Velocity Methanol 300. m 32.0 g 38.0 g Velocity Methanol 327 meters 2 - AHC - Chapter 14 - Graham's Law Worksheet - Answers - V8

3 3. Which gas diffuses faster at the same temperature, carbon dioxide or xenon To three significant figures, how much faster does it diffuse We are solving for the ratio of the rates of diffusion. In this type of problem it is generally understood that, unless told otherwise, we are comparing the faster moving gas, the lighter gas, to the slower moving gas, the heavier gas. Thus, since carbon dioxide is the lighter gas, it will diffuse faster. Therefore, we will make gas 1 carbon dioxide. Gas 1 (Lighter Gas) Gas 2 (Heavier Gas) Name Carbon Dioxide Xenon Formula CO 2 Xe 44.0 g 131 g Velocity - - Rate Carbon Dioxide Rate Xenon Xenon Carbon Dioxide Since we are solving for the ratio of the rates of diffusion, the left side of the equation can be expressed as one variable: Rate Carbon Dioxide Rate Xenon x Rate Carbon Dioxide Rate Xenon Xenon Carbon Dioxide x Xenon Carbon Dioxide x 131 g 44.0 g 1.73 Carbon dioxide will diffuse 1.73 times faster than xenon. 3 - AHC - Chapter 14 - Graham's Law Worksheet - Answers - V8

4 4. Which gas diffuses faster at the same temperature, nitrogen or ammonia To three significant figures, how much faster does it diffuse We are solving for the ratio of the rates of diffusion. In this type of problem it is generally understood that, unless told otherwise, we are comparing the faster moving gas, the lighter gas, to the slower moving gas, the heavier gas. Thus, since ammonia is the lighter gas, it will diffuse faster. Therefore, we will make gas 1 ammonia. Gas 1 (Lighter Gas) Gas 2 (Heavier Gas) Name Ammonia Nitrogen Formula NH 3 N g 28.0 g Velocity - - Rate Ammonia Rate Nitrogen Nitrogen Ammonia Since we are solving for the ratio of the rates of diffusion, the left side of the equation can be expressed as one variable: Rate Ammonia Rate Nitrogen x x Nitrogen Ammonia x 28.0 g 17.0 g 1.28 Ammonia will diffuse 1.28 times faster than nitrogen. 4 - AHC - Chapter 14 - Graham's Law Worksheet - Answers - V8

5 5. A helium atom travels an average of 1,000. m/s at 250. o C. How fast would an atom of radon travel at the same temperature Name Helium Radon Formula He Rn Velocity 4.00 g 1,000. m 222 g m Velocity He Velocity Rn Rn He Cross Multiply To Get The Variable in the Numerator. ( Velocity He )( He ) ( Velocity Rn )( Rn ) Rn ( Velocity He ) He Velocity Rn ( Velocity Rn )( Rn ) Rn ( Velocity He )( He ) Rn Velocity Rn 1,000. m 222 grams e 4.00 grams e Velocity Rn 134 m 5 - AHC - Chapter 14 - Graham's Law Worksheet - Answers - V8

6 6. A nitrogen gas ecule travels at about 500. m/s at room temperature. How fast would a ecule of ethanol, C 2 H 5 OH, travel at the same temperature Name Nitrogen Ethanol Formula N 2 C 2 H 5 OH Velocity 28.0 g 500. m 46.1 g m Velocity N2 Velocity C2 H 5 OH C2 H 5 OH N2 Cross Multiply To Get The Variable in the Numerator. ( Velocity N2 )( N2 ) ( Velocity C 2 H 5 OH )( C2 H 5 OH ) ( Velocity N2 )( N2 ) C2 H 5 OH Velocity C2 H 5 OH Velocity N2 ( Velocity C2 H 5 OH )( C2 H 5 OH ) C2 H 5 OH N2 C2 H 5 OH Velocity C2 H 5 OH 500. m 28.0 grams e 46.1 grams e Velocity C2 H 5 OH 390. m 6 - AHC - Chapter 14 - Graham's Law Worksheet - Answers - V8

7 7. Helium gas effuses through an opening at a rate times faster than that of unknown gas. What is the ecular mass of this unknown gas Name Helium Unknown Formula He g Velocity - - g Rate of Effusion He Rate of Effusion Unknown He Rate of Effusion He Rate of Effusion Unknown He ( 2.000) ( He ) g g g ( ) g g 7 - AHC - Chapter 14 - Graham's Law Worksheet - Answers - V8

8 8. An unknown gas effuses through an opening at a rate times that of helium gas. What is the ecular mass of this unknown gas Name Unknown Helium Formula He g g Velocity - - Rate of Effusion Unknown Rate of Effusion He He Rate of Effusion Unknown Rate of Effusion He He He g g g ( ) g g 8 - AHC - Chapter 14 - Graham's Law Worksheet - Answers - V8

Gas Law Worksheets - WS: Boyle s and Charles Law

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