A microscopic view. Solid rigid body. Liquid. Fluid. Incompressible. Gas. Fluid. compressible
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1 Hello! I m Chris Blake, your lecturer for the rest of semester We ll cover: fluid motion, thermal physics, electricity, revision MASH centre in AMDC daily My consultation hours: Tues Wayne s consultation hours: Thurs cblake@swin.edu.au
2 Fluid Motion Density and Pressure Hydrostatic Equilibrium and Pascal s Law Archimedes' Principle and Buoyancy Fluid Dynamics Conservation of Mass: Continuity Equation Conservation of Energy: Bernoulli s Equation Applications of Fluid Dynamics
3 A microscopic view Solid rigid body Liquid Fluid Incompressible Gas Fluid compressible
4 What new physics is involved? Fluids can flow from placeto-place Their density can change if they are compressible (for example, gasses) Fluids are pushed around by pressure forces An object immersed in a fluid experiences buoyancy
5 Density The density of a fluid is the concentration of mass dddddddddddddd = mmmmmmmm vvvvvvvvvvvv ρρ = mm VV UUUUUUUUUU aaaaaa kkkk mm 3 Mass = 100 g = 0.1 kg Volume = 100 cm 3 = 10-4 m 3 Density = 1 g/cm 3 = 1000 kg m 3
6 The shown cubic vessels contain the stated matter. Which fluid has the highest density? mm 1 kkkk of water at 73 CC mm 1 kkkk of water at 273 CC 0% mm 1 kkkk of water at 273 KK mm 1 kkkk of water at 373 CC
7 Pressure Pressure is the concentration of a force the force exerted per unit area Greater pressure! (same force, less area) Exerts a pressure on the sides and through the fluid
8 Pressure pp = FF AA Units of pressure are N/m 2 or Pascals (Pa) 1 N/m 2 = 1 Pa Atmospheric pressure = 1 atm = kpa = 1 x 10 5 N/m 2
9 A What is responsible for the force which holds urban climber B in place when using suction cups. vvvvvvvvvvvv B 1. Theforce of friction 2. Vacuum pressure exerts a pulling force 3. Atmospheric pressure exerts a pushing force 4. The normal force of the glass. 0%
10 Hydrostatic Equilibrium Pressure differences drive fluid flow If a fluid is in equilibrium, pressure forces must balance Pascal s law: pressure change is transmitted through a fluid
11 Hydrostatic Equilibrium with Gravity Derivation: PP + dddd AA pppp = mmmm dddd AA = ρρ AA ddd gg dddd ddd = ρρρρ PP = PP 0 + ρρρρρ Pressure in a fluid is equal to the weight of the fluid per unit area above it: PP = PP 0 + ρρρρρ
12 Consider the three open containers filled with water. How do the pressures at the bottoms compare? A. B. C. 1. PP AA = PP BB = PP CC 0% 2. PP AA < PP BB = PP CC 3. PP AA < PP BB < PP CC 4. PP BB < PP AA < PP CC 5. Not enough information
13 The three open containers are now filled with oil, water and honey respectively. How do the pressures at the bottoms compare? A. B. C. oil water 1. PP AA = PP BB = PP CC honey 0% 2. PP AA < PP BB = PP CC 3. PP AA < PP BB < PP CC 4. PP BB < PP AA < PP CC 5. Not enough information
14 Calculating Crush Depth of a Submarine Q. A nuclear submarine is rated to withstand a pressure difference of 70 aaaaaa before catastrophic failure. If the internal air pressure is maintained at 1 aaaaaa, what is the maximum permissible depth? PP = PP 0 + ρρggg PP PP 0 = 70 aaaaaa = PPPP ; ρρ = kkkk/mm 3 h = PP PP 0 ρρρρ = = 720 mm
15 Measuring Pressure Q. What is height of mercury (Hg) at 1 aaaaaa? ρρ HHHH = 13.6 gg/cccc 3 PP = PP 0 + ρρρρρ h = PP/ρρρρ h = = 0.75 mm Atmospheric pressure can support a 10 meters high column of water. Moving to higher density fluids allows a table top barometer to be easily constructed. pp = pp 0 + ρρρρρ
16 Pascal s Law Pressure force is transmitted through a fluid Q. A large piston supports a car. The total mass of the piston and car is 3200 kkkk. What force must be applied to the smaller piston? F 2 A 2 A 1 Pressure at the same height is the same! (Pascal s Law) FF 1 AA 1 = FF 2 AA 2 FF 1 = AA 1 AA 2 mmmm = ππ = 490 NN ππ 1.202
17 Gauge Pressure Gauge Pressure is the pressure difference from atmosphere. (e.g. Tyres) PP aaaaaaaaaaaaaaaa = PP aaaaaaaaaaaaaaaaaaa + PP gggggggggg
18 Archimedes Principle and Buoyancy Why do some things float and other things sink?
19 Archimedes Principle and Buoyancy Objects immersed in a fluid experience a Buoyant Force! FF BB = mm wwwwwwwwww gg = ρρ wwwwwwwwww VVVV WW = mm ssssssssss gg = ρρ ssssllllll VVVV The Buoyant Force is equal to the weight of the displaced fluid!
20 Archimedes Principle and Buoyancy The hot-air balloon floats because the weight of air displaced (= the buoyancy force) is greater than the weight of the balloon The Buoyant Force is equal to the weight of the displaced fluid!
21 Which of the three cubes of length ll shown below has the largest buoyant force? water stone wood water F B F B F B m 1 g m 2 g m 3 g A. B. C. 1. wwwwwwwwww 2. ssssssssss 3. wwwwwwww 4. tttttt bbbbbbbbbbbbbb ffffffffff iiii tttttt ssssssss 5. Not enough information 0%
22 Example Archimedes Principle and Buoyancy Q. Find the apparent weight of a 60 kkkk concrete block when you lift it under water, ρρ cccccccccccccccc = 2200 kkkk/mm 3 Evaluate Interpret Water provides a buoyancy force F net = mg Fb = wapparent Apparent weight should be less F Develop = m g = ρ b disp water water Vg ρwatermg wapp = mg F b ρcon m ρwater ρ con = w V app = mg(1 ) ρcon m 1000 V = = (1 ) = 321 N w = mg ρ 2200 con Assess The Buoyant Force is equal to the weight of the displaced fluid.
23 Floating Objects Q. If the density of an iceberg is 0.86 that of seawater, how much of an iceberg svolume is belowthe sea? BBBBBBBBBBBBBBBB ffffffffff FF BB = wwwwwwwwwww oooo wwwwwwwwww dddddddddddddddddd VV ssssss = ssssssssssssssssss vvvvvvvvvvvv FF BB = mm wwwwwwwwww gg = ρρ wwwwwwwwww VV ssssss gg IIII eeeeeeeeeeeeeeeeeeeeee, FF BB = wwwwwwwwwww oooo iiiiiiiiiiiiii FF BB = mm iiiiii gg = ρρ iiiiii VV iiiiii gg ρρ wwwwwwwwww VV ssssss gg = ρρ iiiiii VV iiiiii gg VV ssssss VV iiiiii = ρρ wwwwwwwwww ρρ iiiiii = 0.86
24 A beaker of water weighs ww 1. A block weighting ww 2 is suspended in the water by a spring balance reading ww 0% 3. Does the scale read 1. ww ww 11 + ww ww 11 + ww ww 11 + ww 22 ww ww 11 + ww 33 ww scale
25 Centre of Buoyancy The Centre of Buoyancy is given by the Centre of Mass of the displaced fluid. For objects to float with stability the Centre of Buoyancy must be above the Centre of Mass of the object. Otherwise Torque yield Tip!
26 Fluid Dynamics Laminar (steady) flow is where each particle in the fluid moves along a smooth path, and the paths do not cross. Streamlines spacing measures velocity and the flow is always tangential, for steady flow don t cross. A set of streamlines act as a pipe for an incompressible fluid Non-viscous flow no internal friction (water OK, honey not) Turbulent flow above a critical speed, the paths become irregular, with whirlpools and paths crossing. Chaotic and not considered here.
27 Conservation of Mass: The Continuity Eqn. The water all has to go somewhere The rate a fluid enters a pipe must equal the rate the fluid leaves the pipe. i.e. There can be no sources or sinks of fluid.
28 Conservation of Mass: The Continuity Eqn. A 1 A 2 fluid in fluid out v 1 v 2 Q. How much fluid flows across each area in a time tt: v 1 t v 2 t A 1 A 2 m = ρv1 = ρ A1 v1 t m = ρv2 = ρ A2v2 t flow rate : m t = ρ Av continuity eqn : A v = A v
29 Conservation of Mass: The Continuity Eqn. Q. A river is 40m wide, 2.2m deep and flows at 4.5 m/s. It passes through a 3.7-m wide gorge, where the flow rate increases to 6.0 m/s. How deep is the gorge? AA 1 = ww 1 dd 1 AA 2 = ww 2 dd 2 CCCCCCCCCCCCCCCCCCCC eeeeeeeeeeeeeeee AA 1 vv 1 = AA 2 vv 2 ww 1 dd 1 vv 1 = ww 2 dd 2 vv 2 dd 2 = ww 1dd 1 vv 1 ww 2 vv 2 = = 18 mm
30 Conservation of Energy: Bernoulli s Eqn. What happens to the energy density of the fluid if I raise the ends? v 1 t y 2 y 1 v 2 t Energy per unit volume p 1 + ρ v1 + ρ g y 1 = p2 + ρ v2 + ρ g y2= 2 2 const Total energy per unit volume is constant at any point in fluid. 1 p + ρ v 2 + ρ g y = 2 const
31 Conservation of Energy: Bernoulli s Eqn. Q. Find the velocity of water leaving a tank through a hole in the side 1 metre below the water level. PP ρρρρ2 + ρρρρρρ = cccccccccccccccc AAAA ttttt tttttt: PP = 1 aaaaaa, vv = 0, yy = 1 mm AAAA ttttt bbbbbbbbbbbb: PP = 1 aaaaaa, vv =?, yy = 0 mm PP + ρρρρρρ = PP ρρρρ2 vv = 2gggg = = 4.4 mm/ss
32 Which of the following can be done to increase the flow rate out of the water tank? h 1. Raise the tank ( HH) 2. Reduce the hole size 3. Lower the water level ( hh) 4. Raise the water level ( hh) 5. None of the above HH 0%
33 Summary: fluid dynamics Continuity equation: mass is conserved! ρρ vv AA = cccccccccccccccc For liquids: ρρ = cccccccccccccccc vv AA = cccccccccccccccc (DDDDDDDDDDDDDD ρρ, vvvvvvvvvvvvvvvv vv, pppppppp aaaaaaaa AA) Bernoulli s equation: energy is conserved! PP ρρρρ2 + ρρρρρρ = cccccccccccccccc (PPPPPPPPPPPPPPPP PP, dddddddddddddd ρρ, vvvvvvvvvvvvvvvv vv, heeeeeeeee yy)
34 Bernoulli s Effect and Lift PP ρρρρ2 + ρρρρρρ = cccccccccccccccc Newton s 3 rd law (air pushed downwards) Lift on a wing is often explained in textbooks by Bernoulli s Principle: the air over the top of the wing moves faster than air over the bottom of the wing because it has further to move (?) so the pressure upwards on the bottom of the wing is smaller than the downwards pressure on the topof the wing. Is that convincing? So why can a plane fly upside down?
35 Chapter 15 Fluid Motion Summary Density and Pressure describe bulk fluid behaviour Pressure in a fluid is the same for points at the same height In hydrostatic equilibrium, pressure increases with depth due to gravity The buoyant force is the weight of the displaced fluid Fluid flow conserves mass (continuity eq.) and energy (Bernoulli s equation) A constriction in flow is accompanied by a velocity and pressure change. Reread, Review and Reinforce concepts and techniques of Chapter 15 Examples 15.1, 15.2 Calculating Pressure and Pascals Law Examples 15.3, 15.4 Buoyancy Forces: Working Underwater + Tip of Iceberg Examples 15.5 Continuity Equation: Ausable Chasm Examples 15.6, 15.7 Bernoulli's Equation Draining a Tank and Venturi Flow
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