Find Mean, Median, Mode, and Outlier

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1 SS SDA G6.S.5.c 2 dentify Giving the mode(s) quantitative for sets measures of categorical of center (median data, and/or the mean) and variability (interquartile mode(s), range median, and/or and mean any absolute apparent deviation), outliers as for well numerical as describing data any overall pattern sets. and any striking deviations from the overall pattern with reference to the context in which the data were gathered. UNDRLYNG SKLLS AND ONS: order numbers; addition; division Find Mean, Median, Mode, and Outlier Key d e a he median of a set of data is the middle number when the data are put in order. When there are two middle numbers, the median is the mean (average) of the two middle numbers. An outlier is a number that does not seem to fit within the range of the data. t is either much lower or much higher than the other numbers. he mean is the average of a set of data. he mean is found by finding the sum of the data and then dividing the sum by the number of data. A mode is a number or category that is listed most often in a set of data. Sometimes there is no mode. Sometimes there is more than one mode. x a m p l Miguel and seven friends are checking to see how many raisins are in a snack box. he table shows what they found out. Raisins in a Snack Box Box Raisins What is the median of Miguel s data? he median of the data is the middle number. o find the median, write the numbers in order from least to greatest. hen identify the number that is in the middle. f you have a data set with an even number of data, find the average of the two middle numbers. 42, 44, 45, 45, 46, 46, 48, 59 he median of these data is Which is an outlier? Why? , because most of the boxes have fewer than 50 raisins each. What is the mode of the data? Look for the numbers that are listed most often. hese data have two modes, 45 and 46. What is the average number of raisins per box? Add all the numbers together and divide by 8. Round to the nearest whole number is about 47 raisins per box. page 354 hapter 30 Lesson 3

2 in a mean 12 cubes median 12 mode 12 outliers 7 ime of a ime 50 minutes 4 10 minutes 40 minutes mean 2 hr 6 min mode none median 1 hr 50 min outliers 3 hr 5 min rice mean $40 median $40 mode $40 outliers none rice of a Bike Helmet $60 $40 $25 $40 $35 Data Analysis MR 3 Her average over 3 tries is 25. On her fourth try she did only 1 ossible answer: Her average will go down. f her average is 25 over 3 tries then the total is 75. Add 13 and divide by 4 to find the average over 4 tries. Now it is 2 hapter 30 Lesson 3 page 355

3 at home! in a mean 12 median 15 mode 13 outliers 8 ime of a ime 30 minutes mean 1 hr 58 min median 1 hr 35 min mode none outliers 3 hr 5 min rice mean $31 median $30 mode $25 outliers none rice of a Backpack $40 $30 $25 $25 $35 Data Analysis MR 3 Her average over 3 tries is 30. On her fourth try she did only 2 ossible answer: Her average will go down. f her average is 30 over 3 tries then the total is 90. Add 22 and divide by 4 to find the average over 4 tries. Now it is 28. page 238 Home Resource and Homework hapter 30 Lesson 3

4 in a mean 12 cubes median 12 mode 12 outliers 7 ime of a ime 50 minutes 4 10 minutes 40 minutes mean 2 hr 6 min mode none median 1 hr 50 min outliers 3 hr 5 min rice mean $40 median $40 mode $40 outliers none rice of a Bike Helmet $60 $40 $25 $40 $35 Data Analysis MR 3 Her average over 3 tries is 25. On her fourth try she did only 1 ossible answer: Her average will go down. f her average is 25 over 3 tries then the total is 75. Add 13 and divide by 4 to find the average over 4 tries. Now it is 2 hapter 30 Lesson 3 Student Book age page 355

5 at home! in a mean 12 median 15 mode 13 outliers 8 ime of a ime 30 minutes mean 1 hr 58 min median 1 hr 35 min mode none outliers 3 hr 5 min rice mean $31 median $30 mode $25 outliers none rice of a Backpack $40 $30 $25 $25 $35 Data Analysis MR 3 Her average over 3 tries is 30. On her fourth try she did only 2 ossible answer: Her average will go down. f her average is 30 over 3 tries then the total is 90. Add 22 and divide by 4 to find the average over 4 tries. Now it is 28. page 238 Home Resource and Homework hapter 30 Lesson 3

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