Terrestrial Observations Chart Plot - Chesapeake Bay Entrance - Operational Level

USCG 00326-NP-5 The following questions are based on chart 12221TR, Chesapeake Bay Entrance, and the supporting publications. The draft of your tow is 27 feet (8.2 meters). Use 10 W variation where required. There is no gyro error. Deviation Table HDG. MAG. 000º 030º 060º DEV. 0º 1º W 2º W HDG. MAG. 120º 150º 180º DEV. 2º W 1º W 1º E HDG. MAG. 240º 270º 300º DEV. 3º E 3º E 2º E 1) Your 0200 position is LAT 37 23.5' N, LONG 76 09.2' W. Your speed is 8 knots, and your course is 095 T. Which statement is TRUE? Plot your position, lay down your course and speed and then determine which distracter is the most accurate. 00326-np-5.pdf Page 1 of 26 Copyright 2009 - LAPWARE, LLC

A) INCORRECT - Depth is in feet not fathoms. B) INCORRECT - Wolf Trap Light is the closest major aid to navigation. C) CORRECT - how ever the question does not specify the length of the tow or whether you are pushing ahead, towing alongside or astern. If you drift too far south then the sunken wreck can pose a problem with your 27 foot depth tow. D) INCORRECT - You will pass NORTH of the disposal area. A) The depth of the water in your vicinity is about 38 to 40 fathoms (69.1 meters to 72.7 meters). B) The closest major aid to navigation is New Point Comfort. C) You are less than a mile from a sunken wreck which could interfere with your tow. ANSWER D) You will pass through a disposal area on your present course. 00326-np-5.pdf Page 2 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00327-NP-5 2) At 0315, you obtain the following bearings: Wolf Trap Light bearing 271 true Old Plantation Flats Light bearing 179 true What is the true course from this position to the entrance of York Spit Channel? Determine the position of the lights that the bearings were taken on and lay down your bearings. From this 0315 fix, lay down your course to the entrance of York Spit Channel. 00327-np-5.pdf Page 3 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00328-NP-5 3) From your 0315 position, what time can you expect to reach York Spit Channel Buoys "37" and "38"? Measure off the distance to run from your 0315 fix to a point between buoys 37 and "38". You should get approximately 6.7 miles. Your speed is 8.0 knots. A) 0423 B) 0417 C) 0412 D) 0405 ANSWER Distance = Speed x Time Time = Distance / Speed Time = 6.7 / 8.0 Time = 0.8375 hours Time = 50.25 minutes 0315 50 0405 ETA 00328-np-5.pdf Page 5 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00329-NP-5 4) The engineer has advised that it will be necessary to secure the gyrocompass and the electronic equipment. From your 0315 position, what is your course per standard magnetic compass to York Spit Channel Buoy "38", if there is no current? True Course 208º T Variation 10º W Magnetic 218º Deviation 2º E Compass 216º psc 216 psc See the plot on the next page. A) 218 psc B) 216 psc ANSWER C) 214 psc D) 212 psc 00329-np-5.pdf Page 6 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00330-NP-5 5) Which chart could you use for greater detail of the area at the south end of York Spit Channel? Since the question asks for the chart detail at the SOUTH end of the York Spit Channel make sure that is the area you are looking at. 12222 A) 12254 B) 12226 C) 12224 D) 12222 ANSWER 00330-np-5.pdf Page 8 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00331-NP-5 6) You leave York Spit Channel at buoy "14" at 0600 with an engine speed of 12 knots. You receive orders to rendezvous with the tug "Quicksilver" and her tow at Hog Island Bell Buoy "12". What is your ETA at the rendezvous point, if you pass through Chesapeake Channel to buoy "CBJ", through the outbound traffic separation lane to buoy "NCA" (LL#375), and then to the rendezvous point? This question requires you to lay down various courses from to your rendezvous. I created a total of seven (7) legs totalling a distance of 37.3 miles. Using your engine speed of 12 knots determine your ETA from your 0600 position. Your track lines might be slightly different but the overall distance should be close. Distance = Speed x Time Time = Distance / Speed Time = 37.3 / 12 Time = 3.108 hours Time = 3h 06m 0600 0306 See the plot on the next page. 0906 A) 0935 B) 0910 ANSWER C) 0850 D) 0830 00331-np-5.pdf Page 9 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00332-NP-5 7) You arrive at the rendezvous point, secure the tow, and head back southward. At 1200, you take the following bearings: Sand Shoal Inlet South Light bearing 289 pgc Cape Charles Light bearing 240 pgc What is your 1200 position? Sand Shoal Inlet South Light 289º pgc Gyro Error 0º Bearing True 289º T Cape Charles Light 240º pgc Gyro Error 0º Bearing True 240º T After determining your TRUE bearings plot your position and determine your latitude and longitude at 1200. See the plot on the next page. A) LAT 37 15.0' N, LONG 75 37.5' W ANSWER B) LAT 37 16.0' N, LONG 75 38.0' W C) LAT 37 17.0' N, LONG 75 39.5' W D) LAT 37 19.0' N, LONG 75 40.5' W 00332-np-5.pdf Page 11 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00333-NP-5 8) From your noon position, if there is no set and drift, what is your course per standard magnetic compass to the "NCA" (LL #375) buoy? Lay down your course from your 1200 postion to a point just off of buoy "NCA". You should get 209 T. Now convert that to a compass heading. A) 221 psc B) 219 psc C) 217 psc ANSWER D) 215 psc True Course 209º T Variation 10º W Magnetic 219º Deviation 2º E Compass 217º psc See the plot on the next page. 00333-np-5.pdf Page 14 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00334-NP-5 9) Your gyro and electronic gear are again operating. At 1710, Chesapeake Light bears 137 pgc at 6.6 miles. The current is setting 160 T at 2 knots. At your speed of 6 knots, what is your true course to steer to remain in the inbound traffic lane? Chesapeake Light 137º G Set 160º T Gyro Error 0º 2 kts True Bearing 137º T Speed 6 kts After determining your True bearing, lay down your 1710 position. Determine your True heading to remain in the inbound traffic lane. You should get about 250 T. On your maneuvering board, plot your desired course, apply your set and drift and determine your course to steer while turning 6 knots. 00334-np-5.pdf Page 16 of 26 Copyright 2009 - LAPWARE, LLC

Lay down your true heading desired (250 T) from the center of the plot. From the center of the plot lay down your Set of 160 T and Drift of 2.0 knots. From the END of the Set and Drift line swing an arc of 6.0 miles. Where it intersects your desired heading (250 T) is your course to steer. Parallel this line to the center of the plot to determine your actual course to steer (269.5 T). 269.5 T 250 T Speed arc of Set 160 T A) 250 B) 261 C) 265 D) 269 ANSWER 269.5 T 00334-np-5.pdf Page 17 of 26 Copyright 2009 - LAPWARE, LLC

LAW OF SINES B 250 A = 250-160 = 090 160 2 mi 6 miles a b c = = Sin A Sin B Sin C 6 2 = Sin 90 Sin B Sin B = 2 x Sin 90 6 Sin B = 2 = 0.333333 6 B = 19.5º 250.0º 19.5º 269.5º 00334-np-5.pdf Page 18 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00335-NP-5 10) At 1810, you obtain the following bearings: Cape Charles Light bearing 005 pgc Cape Henry Light bearing 251.5 pgc What is your position? Chesapeake Light 005º G Cape Henry Light 251.5º G Gyro Error 0º Gyro Error 0.0º True Bearing 005º T True Bearing 251.5º T Plot your bearings and determine your position. 00335-np-5.pdf Page 19 of 26 Copyright 2009 - LAPWARE, LLC

36 56.9' N 75 55.6' W A) LAT 36 56.0' N, LONG 75 58.5' W B) LAT 36 55.4' N, LONG 75 56.0' W C) LAT 36 56.8' N, LONG 75 55.6' W ANSWER D) LAT 36 57.4' N, LONG 75 54.6' W 00335-np-5.pdf Page 20 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00336-NP-5 11) What speed have you made good from 1710 to 1810? Measure your distance run from your 1710 to your 1810 position. Since it is exactly one hour the distance measured will be your speed made good. 6.13 knots Note: the nearest distracter is 6.3 knots and is the obvious correct selection. However, to confirm this answer I decided to solve the vessels positon from the Chesapeake Light with the bearing and range provided in question 334. Using tht position andmy position determined for my 1810 position I then solved the course and distance between 1710 and 1810. My mercator solutions resulted in a speed of 6.17 knots. A) 6.3 knots ANSWER B) 5.5 knots C) 4.9 knots D) 4.2 knots 00336-np-5.pdf Page 21 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00337-NP-5 12) If you make good a speed of 6.0 knots from your 1810 position, what is your ETA at Chesapeake Channel Lighted Bell Buoy "2C"? Measure the distance to run from your 1810 position to a point abeam of Chesapeake Channel Light Bell Buoy "2C". You should get a distance of approximately 2.3 miles. Determine your ETA with a speed made good of 6.0 knots. A) 1900 B) 1855 C) 1845 D) 1833 ANSWER Distance = Speed x Time Time = Distance / Speed Time = 2.3 / 6.0 Time = 0.38 hours Time = 23 minutes 1810 23 1833 ETA 00337-np-5.pdf Page 22 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00338-NP-5 13) You passed Cape Henry Light at 0730 outbound at maximum flood. What approximate current can you expect on entering Chesapeake Channel? (NOTE: outbound should probably be inbound!) Sorry, but this question is just plain dumb. First, since Chesapeake Channel is just 4-5 miles NORTH of Cape Henry Light you would obviously experience a flooding current. Since no year or date is provided no additional information can be looked up or determined from the current tables. Secondly, question 12 requests the mariner to calculate their ETA at Chesapeake Channel Lighted Bell Buoy "2C". Answer is 1833. NOW, all of a sudden we are passing Cape Henry Light at 0730. Buoy "2C" is less then 3 miles from the Chesapeake Channel entrance. What the hell have we been doing from 1833 at buoy "2C" to a point where we enter the Chesapeake Channel entrance at 0730 outbound no less? That's almost 12 full hours and now we are heading in the opposite direction with no explanation as to why. It just does NOT make sense even though the answer to this question is obvious. A) Slack before ebb B) Slack before flood C) Flood current ANSWER D) Ebb current 00338-np-5.pdf Page 23 of 26 Copyright 2009 - LAPWARE, LLC

Page 134 sandy hills about 80 feet high A) rocky with pine scrubs B) low wetlands C) sandy hills about eighty feet high ANSWER D) low and thinly wooded with many beach houses 00339-np-5.pdf Page 25 of 26 Copyright 2009 - LAPWARE, LLC

USCG 00340-NP-5 15) Inbound, the color of Cape Henry Light will. We are INBOUND again. I guess our rudder is stuck hard over! NMC going in circles! A) INCORRECT - but it almost makes sense since we are alternating our direction inboound, outbound and inbound again. B) INCORRECT - the color will change BEFORE you reach the bell buoy NOT AFTER. C) INCORRECT - the color of the light will change to a red sector and NOT remain the same. D) CORRECT - as you approach buoy "2C" INBOUND the light will change to red. A) alternate regardless of your position B) change after you reach Chesapeake Channel Lighted Bell Buoy "2C" C) remain the same D) change before you reach Chesapeake Channel Lighted Bell Buoy "2C" ANSWER 00340-np-5.pdf Page 26 of 26 Copyright 2009 - LAPWARE, LLC