Name: Class: Date: ID: A Practice Test #2 Multiple Choice Identify the choice that best completes the statement or answers the question. 1. What reading is shown on the caliper image below? a. 45.65 mm c. 40.15 mm b. 42.50 mm d. 40.00 mm 2. This quarter is approximately 2.5 cm wide. Estimate how long the line is using the quarter as a referent. a. 5.0 cm c. 10.0 cm b. 7.5 cm d. 12.5 cm 3. Identify the most appropriate imperial measurement unit to use when estimating the perimeter of this figure. a. foot c. mile b. inch d. yard 1
Name: ID: A 4. The flying distance from Dawson City to Whitehorse is 540 km. The distance shown on the map is 4 cm. What is the scale of the map as a ratio in lowest terms? a. b. 54 000 000 1 4 54 000 000 c. d. 13 500 000 4 1 13 500 000 5. Ben measures the length of the street he lives on to be 90 000 cm. Which of the following measurements is the same length? a. 0.9 km c. 90 km b. 0.9 m d. 90 m 6. Determine the measurement shown on the imperial caliper. a. 60.16 in. c. 32.00 in. b. 45.10 in. d. 27.42 in. 7. Which line is closest to 3 in. long? 4 a. c. b. d. 8. Which of the following measurements is equal to 9 yd, to the nearest hundredth? a. 5.59 m c. 9.84 m b. 8.23 m d. 9.00 m 2
Name: ID: A 9. A low bridge has a posted height of 7 ft 6 in. If your truck is 2.3 m high, how many centimetres over or under the bridge height will it be? a. 1.4 cm over c. 2.36 cm over b. 1.4 cm under d. 2.36 cm under 10. Monica is putting a rectangular patio in her yard. Patio stones come in squares measuring 1 ft by 1 ft. She wants the dimensions of the patio to be 8 stones by 6 stones. What will the area of the patio be, to the nearest hundredth of a square metre? a. 4.46 m 2 c. 40.13 m 2 b. 5.33 m 2 d. 48.00 m 2 Completion Complete each statement. 1. Canada s official measurement system is the _. 2. An item that a person might use to approximate a measurement is called a(n) _. 3. All SI linear measurements are derived from the _. 4. Twenty feet is equivalent to _ inches. 5. To one decimal place, the equivalent of 19 yd is _ m. Matching Match each imperial measurement to its equivalent SI measurement. An SI measurement may be used more than once or not at all. a. 1.28 m d. 63.4 mm b. 22.6 cm e. 6.40 m c. 24.2 km f. 0.004 km 1. 7 yd 2. 4.48 yd 3. 15 mi 4. 4.2 ft 5. 8.9 in. Short Answer 1. Jennifer is 9 in. taller than her sister. If Jennifer is 115 cm tall, how tall is her sister, to the nearest centimetre? 3
Name: ID: A 2. Erin jogs 12 times around the block each morning to stay fit. The block measures 648 ft by 324 ft. a) What is the perimeter of the block? b) How many yards does Erin jog each morning? 3. A computer game disk with the handbook needs a box 19 cm by 14 cm by 1.5 cm in size. What is the total amount of plastic wrapping needed to cover the entire box if 66 cm 2 is needed to allow for the overlapping at the edges? 4. In the figure shown below, each box is a cube that measures 0.5 m on each side. Two boxes are completely hidden. One is hidden under the pile on the left and one is directly behind that one, to give a total of 10 boxes. If the arrangement of boxes sits on the floor, what surface area is exposed to view? 5. Lori wants to laminate a rectangular poster that measures 9 ft by 6 ft. a) What is the area of the poster in square feet? b) What is the area of the poster in square yards? c) The store charges $1.65/yd 2 for lamination. How much will it cost to laminate the poster? Problem 1. Hal needs a 4 ft by 4 ft square of poster board for a presentation. a) What is the area of the poster board, in square feet? b) What is the area of the poster board, to the nearest tenth of a square yard? Show your calculations in more than one way. c) The store charges $0.25/m 2. How much will the sheet cost? 4
Name: ID: A Use this visual to answer the question(s) that follow. 2. How much plastic would you need to cover the surfaces of all the windows in the house above? Express your answer to the nearest square metre. 3. A cylindrical map case has two flat end caps. The case is 200 cm long and 8 cm in diameter. What is the total surface area, to the nearest tenth of a square inch, of the outside of the case when both ends are capped? 4. A Canadian football field is 110 yd long. An American football field is 100 yd long. How many feet longer is the Canadian field? 5. Elaine wants to replace her bedroom floor. Hardwood flooring costs $4.00 per square foot plus $2.00 per square foot for installation. The room is rectangular and measures 3 m by 4 m. a) How much would it cost to buy the hardwood flooring? b) How much would it cost to install the hardwood flooring? c) What is the total cost of resurfacing the floor? 5
Practice Test #2 Answer Section MULTIPLE CHOICE 1. ANS: D PTS: 1 DIF: A OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: caliper measuring instruments SI 2. ANS: B PTS: 1 DIF: B OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: referent SI 3. ANS: B PTS: 1 DIF: B OBJ: Section 1.2 NAT: M1 TOP: Imperial Measurement KEY: estimate imperial 4. ANS: D PTS: 1 DIF: B OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: conversion kilometres to centimetres scale SI 5. ANS: A PTS: 1 DIF: B OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: conversion centimetres to kilometres SI 6. ANS: D PTS: 1 DIF: B OBJ: Section 1.2 NAT: M1 TOP: Imperial Measurement KEY: caliper imperial inch measuring instruments 7. ANS: C PTS: 1 DIF: A OBJ: Section 1.2 NAT: M1 TOP: Imperial Measurement KEY: measure imperial inch 8. ANS: B PTS: 1 DIF: A OBJ: Section 1.3 KEY: conversion imperial to SI yards to metres 9. ANS: A PTS: 1 DIF: C OBJ: Section 1.3 KEY: centimetre conversion foot imperial inch metre SI 10. ANS: A PTS: 1 DIF: B OBJ: Section 1.3 KEY: area conversion foot imperial metre SI square feet to square metres COMPLETION 1. ANS: SI (Système International d Unités) PTS: 1 DIF: A OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: SI 2. ANS: referent PTS: 1 DIF: A OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: referent 3. ANS: metre PTS: 1 DIF: A OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: metre SI 1
4. ANS: 240 PTS: 1 DIF: B OBJ: Section 1.2 NAT: M1 TOP: Imperial Measurement KEY: conversion imperial feet to inches 5. ANS: 17.4 PTS: 1 DIF: B OBJ: Section 1.3 NAT: M1 M2 TOP: Converting Between SI and Imperial Systems KEY: conversion imperial to SI yards to metres MATCHING 1. ANS: E PTS: 1 DIF: B OBJ: Section 1.3 KEY: conversion imperial to SI yards to metres 2. ANS: F PTS: 1 DIF: B OBJ: Section 1.3 KEY: conversion imperial to SI yards to kilometres 3. ANS: C PTS: 1 DIF: B OBJ: Section 1.3 KEY: conversion imperial to SI miles to kilometres 4. ANS: A PTS: 1 DIF: B OBJ: Section 1.3 KEY: conversion imperial to SI feet to metres 5. ANS: B PTS: 1 DIF: B OBJ: Section 1.3 KEY: conversion imperial to SI inches to centimetres SHORT ANSWER 1. ANS: 1 in. = 2.54 cm 9 2.54 = 22.86 115 22.86 = 92.14 Jennifer s sister is approximately 92 cm tall. PTS: 1 DIF: B OBJ: Section 1.3 NAT: M1 M2 TOP: Converting Between SI and Imperial Systems KEY: conversion imperial to SI inches to centimetres 2
2. ANS: a) P = 2(648 + 324) = 2(972) = 1944 The perimeter of the block is 1944 ft. b) One time around: 1944 ft = 1944 ft 1 yd 3 ft = 648 yd Six times around: 12(648) = 7776 Erin jogs 7776 yd each morning. PTS: 1 DIF: B OBJ: Section 1.2 NAT: M1 TOP: Imperial Measurement KEY: conversion imperial feet to yards perimeter 3. ANS: Area of front and back faces: A = 2 19 14 = 532 The area of the front and back faces of the box totals 532 cm 2. Area of two long edges: A = 2 19 1.5 = 57 The area of the two long edges of the box totals 57 cm 2. Area of two short edges: A = 2 14 1.5 = 42 The area of the two short edges of the box totals 42 cm 2. Area needed for overlapping = 66 cm 2 Total area of wrapping: A = 532 + 57 + 42 + 66 = 697 The total amount of plastic wrapping needed is 697 cm 2. PTS: 2 DIF: C OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: surface area centimetre SI 3
4. ANS: There are 40 surfaces exposed. Area of each face: A = 0.5 0.5 = 0.25 Each face has a surface area of 0.25 m 2. Total exposed surface area: A = 0.25 40 = 10 The total exposed surface area is 10 m 2. PTS: 1 DIF: D OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: surface area metre SI 5. ANS: a) A = l w = 18 12 = 216 The area of the poster is 216 ft 2. b) A = 18 ft 1 yd 3 ft = 6 yd 4 yd 12 ft 1 yd 3 ft = 24 yd 2 The area of the poster is 24 yd 2. c) Let C represent the total cost to laminate the poster. C = 1.50 24 = 36.00 The cost to laminate the poster is $36.00. PTS: 1 DIF: B OBJ: Section 1.2 NAT: M1 TOP: Imperial Measurement KEY: area conversion imperial feet to yards square feet to square yards 4
PROBLEM 1. ANS: a) A = 4 4 = 16 The area of the poster board is 16 ft 2. b) Method 1 A = 4 ft 1 yd 1 yd 4 ft 3 ft 3 ft = 1.777778 The area of the poster board is 1.8 yd 2. Method 2 A = 16 ft 2 1 yd2 9 ft 2 = 1.777778 yd 2 The area of the poster board is 1.8 yd 2. c) A = 1.777778 yd 2 1 m 2 1.0936yd 2 =Ö 1.486 m 2 Let C represent the total cost of the poster board. C = 1.486 0.25 =Ö 0.37 The poster board will cost $0.37. PTS: 1 DIF: D OBJ: Section 1.3 NAT: M1 M2 TOP: Converting Between SI and Imperial Systems KEY: area conversion imperial feet to yards imperial to SI yards to metres square yards to square metres 2. ANS: There are 10 windows in total. 1 cm = 0.01 m 60 cm = 0.6 m 45 cm = 0.45 m Surface area of the windows: A = 10 0.6 0.45 = 2.7 Expressed to the nearest square metre, you would need 3 m 2 of plastic to cover the windows. PTS: 2 DIF: B OBJ: Section 1.1 NAT: M1 TOP: SI Measurement KEY: area conversion SI centimetres to metres 5
3. ANS: Convert the dimensions to inches. h = 170 cm 1 in. 2.54 cm =Ö 66.9291 in. r = d 2 cm = 16 2 cm = 8 cm = 8 cm 1 in. 2.54 cm =Ö 3.1496 in. Find the area of the cylinder using the formula SA = 2πr 2 + 2πrh. SA = 2πr 2 + 2πrh = 2π(3.1496) 2 + 2π(3.1496)(66.9291) =Ö 1386.83 The total surface area of the map case is 1386.8 in. 2, to the nearest tenth of a square inch. PTS: 2 DIF: D OBJ: Section 1.3 NAT: M1 M2 TOP: Converting Between SI and Imperial Systems KEY: surface area conversion SI to imperial centimetres to inches square centimetres to square inches pi 4. ANS: 110 100 = 10 The Canadian football field is 10 yd longer than the American field. 1 yd = 3 ft 10 3 = 30 The Canadian football field is 30 ft longer than the American field. PTS: 1 DIF: A OBJ: Section 1.2 NAT: M1 TOP: Imperial Measurement KEY: conversion imperial yards to feet 6
5. ANS: Find the area of the floor in square feet. 3.28084 ft 3.28084 ft A = 3 m 4 m 1 m 1 m =Ö 122.439 ft 2 The area of the floor is 122 ft 2. a) Let C floor represent the cost of the flooring. C floor = 122.439 4.00 =Ö 489.76 The cost to buy the flooring is $489.76. b) Let C install represent the cost to install the flooring. C install = 122.439 2.00 =Ö 244.88 The cost to install the flooring is $244.88. c) Let C total represent the total cost to replace the floor. C total = C floor + C install = 489.76 + 244.88 = 734.64 The total cost to replace the floor is $734.64. PTS: 1 DIF: C OBJ: Section 1.3 NAT: M1 M2 TOP: Converting Between SI and Imperial Systems KEY: conversion SI to imperial metres to feet square metres to square feet 7