Name Date ID Integrated Chemistry and Physics (3) Interim Assessment Third Grading Period 1. You are competing in a strength competition with several other students. The contest is to carry a large metal box up three flights of stairs as fast as possible. You carry the box up the stairs in 45 seconds, but the winner of the contest carries the same box up the same stairs in 30 seconds. Compared to the winner of the contest, you do the same amount of work and have the same power. you do less work but have the same amount of power. you do the same amount of work but have less power. you do less work and have less power. 2. You have two jobs to do around your house today. You need to open a stuck window, and you need to tighten a loose screw on a metal chair. You only have two screwdrivers to choose from; a long thin screwdriver with a small handle and a shorter screwdriver with a fat handle. Since screwdrivers can be used as simple machines, you would choose the following tools for each job: the long screwdriver to pry open the window, and the shorter, fat one to tighten the screw the long screwdriver to tighten the screw, and the shorter, fat one to pry open the window the longer screwdriver for both jobs the shorter, fat screwdriver for both jobs 3. Your friend thinks he has a high-powered car. To prove this, he starts his car from rest and accelerates uniformly to 45m/s in 15 seconds. Calculate his car's acceleration during this time interval. 675 m/s 2 3.0 m/s 2 30.0 m/s 2 0.334 m/s 2 Integrated Chemistry and Physics (3) Interim Assessment (3) Page 1
v + v + v + v + t t t t - - (1) (2) (3) (4) - - 4. Which graph of velocity versus time best describes the motion of a car that is moving forward at constant speed? 1 2 3 4 5. A single pulley is attached to the top of the school flag pole. To raise the flag, a student pulls down on the rope which passes over the pulley and lifts the flag. This is an example of a simple machine that reduces the effort force required to raise the flag. reduces the work required to raise the flag. reduces the effort distance required to raise the flag. changes the direction of the force required to raise the flag. 6. You are sitting in the passenger seat of a car that is stopped. The driver then pushes hard on the gas pedal and the car accelerates quickly, while your head snaps backward. The driver then stops by pushing hard on the brake and your head snaps forward. The movements of your head in both of these instances are example of Newton's 1st Law of Motion (Inertia). 2nd Law of Motion (F=ma). 3rd Law of Motion (Action/Reaction). Universal Law of Gravitation. Integrated Chemistry and Physics (3) Interim Assessment (3) Page 2
7. A car moves with constant speed in a straight line. Which of the following statements must be true? No forces are acting on the car. A single constant force is acting on the car. More than one force is acting on the car and the forces are balanced. More than one force is acting on the car and the forces are unbalanced. 8. Two students push on a box from the same side so that the box accelerates across the floor at 5.0 m/s 2. The mass of the box is 10 kg. Assume that there is no friction between the box and the floor. What is the net force on the box as it accelerates across the floor? 2.0 N 0 N 0.5 N 50.0 N 9. A soccer player kicks a soccer ball with his foot. If the force of his foot on the ball is considered the action force, what is the reaction force? The force that his other foot exerts on the ground. The force on the hand of the person who catches it. The force the ball exerts on his foot. The force of the ball on the air. Integrated Chemistry and Physics (3) Interim Assessment (3) Page 3
10. A small football player has a mass of 85 kg. He is assigned to block a larger player, who has a mass of 120 kg. What will be the momentum of the smaller player if he runs at 5.6 m/s toward the larger player? 672 kg m/s 15.2 kg m/s 21.4 kg m/s 476 kg m/s 11. Consider two engines of different sizes. The larger engine has twice as much power as the smaller engine. The smaller engine can do a certain quantity of work in 1 hour. The larger engine can do twice as much work in the same time. twice the time. half the time. one fourth the time. 12. A worker pulls a box weighing 400 N across a wood floor by applying a force P as shown. If the applied force P equals 250 N and the box moves 2 m, how much work is done by the worker? 0 Joules 800 Joules 500 Joules 650 Joules Integrated Chemistry and Physics (3) Interim Assessment (3) Page 4
13. A worker uses a pulley system to raise a heavy wooden box to a third floor apartment. If he uses an 8 pulley system instead of a 4 pulley system, how will this change the amount of work he does? The amount of work will be twice as much with the 4 pulley system. The amount of work will be the same with both pulley systems. The amount of work will be four times as much with the 4 pulley system. The amount of work will be ½ as much with the 4 pulley system. 14. The efficiency of a simple machine is determined by how much work the machine does (work out) compared to how much work the person does (work in). When using a lever to move an object, your hand moves 1 m with an applied force of 15 N. The other end of the lever moves.2 m with a force of 70 N. What is the efficiency of this simple machine? Choose One: 107% 93% 43% 21% Integrated Chemistry and Physics (3) Interim Assessment (3) Page 5
15. You are loading heavy boxes onto a truck with the help of a friend. You lift the heavy boxes directly from the ground up to the truck, while your friend pushes the boxes up a ramp from the ground to the truck. The reason your friend chooses to use the ramp as an inclined plane is because he will be doing less work than you. moving the boxes less distance than you. using more power to move the boxes than you. using less force than you. 16. Cars built today have padded dashboards and airbags installed for the front seat occupants. The purpose of these devices is to reduce injuries to the people when the car stops suddenly. In an accident, the occupants are less likely to be injured because the distance they move during an accident is smaller. impulse they experience during an accident is less. force they experience is reduced. time of impact is reduced. 17. The formula for the velocity (v) of an object that is accelerating (a) from rest for a given time interval (t) can be written as v = a t To use this same formula to solve for the acceleration of the object if you knew the velocity and time, you would change the formula to a = v + t a = vt a = v - t Integrated Chemistry and Physics (3) Interim Assessment (3) Page 6
18. During a classroom laboratory, you measured the distance and time of a bowling ball that was rolling in a straight line down the hallway. The results of your measurements are shown in the table below. Based upon the data given, predict the distance the ball will travel during the next second of motion. Time (s) Distance from the start (m) 0 0 1 4.00 2 7.00 3 9.00.5 m 3.0 m 2.0 m 1.0 m 19. The mechanical advantage of a simple machine is a measure of how much the simple machine multiplies the force or distance of the input. A lever is balanced in the center like a seesaw, and a worker uses the lever to lift a heavy box. If you compare the weight of the box to the force the worker must apply and assume no friction, the mechanical advantage of this simple machine would be approximately 3 2.5 1 Integrated Chemistry and Physics (3) Interim Assessment (3) Page 7
20. In a laboratory activity you are asked by your teacher to investigate the velocity and accelerations of different toys. You select a toy car, wind it up, and run it across the floor while marking its position as each second of time is called out by your teacher. If the distances between the position marks get bigger for each second that the car moves, then you could conclude that the toy car is slowing down. moving at constant velocity. speeding up. moving in a circle. Read For a Little More Distance, Spin Accuracy to answer questions 21, 22, 23, and 24. For a Little More Distance, Spin and Accuracy The all new, high tech tee design optimized for speed and performance; conforms to the USGA rules of golf. Designed and perfected by a specialized engineering team of chemists and golfers, produced by golf tee manufacturer Friction-Less, Inc. After extensive testing, we are pleased to announce that your golf ball is GUARANTEED to come off a Friction-Less golf tee 2 miles an hour faster than off a regular tee, no matter what club or ball you use. PGA Championship golf scores saw significant improvement last year in Duluth, Georgia, where this novel tee design also underwent widespread field testing, and is popularly reported to improve drive distance, speed and accuracy. Many players typically try to improve distance through careful selection of clubs, yet reliance on golf clubs for distance is only part of success; the longest drive and farthest golf ball distances are achieved with minimal interference from the tee; most swing and distance tips overlook this fact. The Patent Pending Friction-Less golf tee is an entirely new concept in golf technology. It has been specifically designed to minimize any influence the golf tee can have on the golf ball. Just strike a golf ball across a conventional golf tee and then strike the ball across the Friction-Less golf tee. That difference you feel is less energy being transferred to the tee. - The first design feature is to minimize the surface area in contact with the golf ball while still providing enough area to easily mount the ball on the tee. - The second design feature is to minimize the force the ball encounters with the edge of the tee by eliminating the sharp edge. - The third design feature is to minimize the friction between the golf ball and the tee surface. This is accomplished by using polytetrafluoroethylene (Teflon ) as the surface material. Teflon has the lowest coefficient of friction of any known solid material. Together these features maximize the effect of the golf club on the golf ball for increased velocity, distance and accuracy. That means better golf! Reference: www.frictionlesstee.com Integrated Chemistry and Physics (3) Interim Assessment (3) Page 8
21. What was the author's purpose in writing this article? To describe a newly developed tee for golf. To explain the many ways to improve at golf. To sell a new golf tee to golfers. To describe the testing procedures for a new golf tee. 22. What physical concept gives this newly developed golf tee its basis for the claims its designer makes? Friction between the golf ball and tee will reduce the velocity of the ball. If the tee weighs less, it will not push on the ball as hard. If the ball is smoother it will travel through the air easier. Hitting a ball further will also mean hitting it more accurately. 23. Why did the author mention the PGA Championship at Duluth, Georgia? To impress golfers from Georgia. To add validity to his test results. To talk about the PGA Championship. To describe a typical golf course. 24. What does the word "significant" mean in the first sentence of the 2nd paragraph? none at all some less than average quite a lot Integrated Chemistry and Physics (3) Interim Assessment (3) Page 9
Name Date ID Integrated Physics and Chemistry (3) Interim Assessment Third Grading Period Answer Document 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24.
Density = heat gained or ( ) = mass in change in specific lost by water ( grams )( temperature )( heat ) distance Speed = time final velocity initial velocity Acceleration = change in time Momentum = mass velocity Force = mass acceleration Work = force distance work Power = time work output % efficiency = 100 work input 1 Kinetic energy = 2 (mass velocity 2 ) Gravitational potential energy = mass acceleration due to gravity height Energy = mass (speed of light) 2 Velocity of a wave = frequency wavelength Current = mass volume voltage resistance Electrical power = voltage current Electrical energy = power time FORMULA CHART for Grades 10 11 Science Assessment Constants/Conversions g = acceleration due to gravity = 9.8 m/s 2 c = speed of light = 3 10 8 m/s speed of sound = 343 m/s at 20 C 1 cm 3 = 1 ml 1 wave/second = 1 hertz (Hz) 1 calorie (cal) = 4.18 joules 1000 calories (cal) = 1 Calorie (Cal) = 1 kilocalorie (kcal) newton (N) = kgm/s 2 joule (J) = Nm watt (W) = J/s = Nm/s volt (V) ampere (A) ohm (Ω) D = Q = (m)( T)(Cp) s = a = p = mv F = ma W = Fd P = % = 100 KE = GPE = mgh E = mc 2 v = f λ I = m v W O W I V R P= VI E = Pt d t v f v i t W t mv 2 2 Centimeters 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 13
1 2 3 4 5 6 7 Periodic Table of the Elements Group 1 IA 1 H 1.008 Hydrogen 2 IIA 3 4 Li Be 6.941 9.012 Lithium Beryllium 11 12 Na Mg 22.990 24.305 Sodium Magnesium 19 20 K Ca 3 4 5 6 7 8 9 IIIB IVB VB VIB VIIB VIII 21 22 23 24 25 26 27 Sc Ti V 39.098 40.08 44.956 47.88 50.942 51.996 54.938 55.847 58.933 Potassium Calcium Scandium Titanium Vanadium Chromium Manganese Iron Cobalt 37 38 39 40 41 42 43 44 45 Cr Mn Rb Sr Y Zr Nb Mo Tc Ru 85.468 87.62 88.906 91.224 92.906 95.94 (98) 101.07 102.906 Rubidium Strontium Yttrium Zirconium Niobium Molybdenum Technetium Ruthenium Rhodium 55 56 57 72 73 74 75 76 77 Cs Ba La Hf Ta W Re Os 132.905 137.33 138.906 178.49 180.948 183.84 186.207 190.23 192.22 Cesium Barium Lanthanum Hafnium Tantalum Tungsten Rhenium Osmium Iridium 87 88 89 104 105 106 107 108 109 Fr Ra Ac Rf Db Sg Bh Hs Mt (223) 226.025 227.028 (261) (262) (263) (262) (265) (266) Francium Radium Actinium Rutherfordium Dubnium Seaborgium Bohrium Hassium Meitnerium Fe Co Rh Ir Lanthanide Series Actinide Series 58 Ce Th Pr Pa Nd U Pm Np Sm 140.12 140.908 144.24 (145) 150.36 Cerium Praseodymium Neodymium Promethium Samarium 90 59 91 60 92 61 93 62 94 Pu 232.038 231.036 238.029 237.048 (244) Thorium Protactinium Uranium Neptunium Plutonium 10 11 IB 28 Ni Pd Pt Atomic number Symbol Atomic mass 29 Cu Ag Au 12 IIB 30 Zn Cd Hg 14 Si 28.086 Silicon 13 IIIA Ga Tl 14 IVA Ge Pb Name 15 VA As 16 VIA In Sn Sb Te I Bi Se Po 17 VIIA Br At 18 VIIIA He 4.0026 Helium 5 6 7 8 9 10 B C N O F Ne 10.81 12.011 14.007 15.999 18.998 20.179 Boron Carbon Nitrogen Oxygen Fluorine Neon 13 14 15 16 17 18 Al Si P S Cl Ar 26.982 28.086 30.974 32.066 35.453 39.948 Aluminum Silicon Phosphorus Sulfur Chlorine Argon 31 32 33 34 35 36 58.69 63.546 65.39 69.72 72.61 74.922 78.96 79.904 83.80 Nickel Copper Zinc Gallium Germanium Arsenic Selenium Bromine Krypton 46 47 48 49 50 51 52 53 54 106.42 107.868 112.41 114.82 118.71 121.763 127.60 126.904 131.29 Palladium Silver Cadmium Indium Tin Antimony Tellurium Iodine Xenon 78 79 80 81 82 83 84 85 86 195.08 196.967 200.59 204.383 207.2 208.980 (209) (210) (222) Platinum Gold Mercury Thallium Lead Bismuth Polonium Astatine Radon 110 Mass numbers in parentheses are those of the most stable or most common isotope. (269) 2 Kr Xe Rn 63 Eu Am 64 Gd Cm 65 Tb Bk 66 Dy Cf 67 Ho 151.97 157.25 158.925 162.50 164.930 167.26 168.934 173.04 174.967 Europium Gadolinium Terbium Dysprosium Holmium Erbium Thulium Ytterbium Lutetium 95 96 97 98 99 Es (243) (247) (247) (251) (252) (257) (258) (259) (262) Americium Curium Berkelium Californium Einsteinium Fermium Mendelevium Nobelium Lawrencium 68 Er 100 Fm 69 Tm 101 Md 70 Yb 102 No 71 Lu 103 Lr Revised October 15, 2001 14