ID : cn-6-decimals [1] Grade 6 Decimals For more such worksheets visit www.edugain.com Answer the questions (1) What is the smallest number that should be subtracted from 15.27 to give a prime number? (2) What is the place 100000 times smaller than the Ten Thousands place called? (3) What do you get when you multiply 5.6 and 2.77? (4) What is the place value of 7 in 2046.8597? (5) At a construction site, there are 9.5 loads of bricks and the total weight of all the loads together is 288.325 kg. Find the weight of one load? (6) How is the number ninety-six and eighty-four hundredths written in decimal form? (7) If the following figure represents 0.15, what is the result of the given problem? (8) A juice cart sells 188.49 liters of grape juice on Thursday and 16.41 liters more than this quantity on Friday. The following day, 11.32 liters less grape juice was sold than the quantity sold on Friday. How many liters of grape juice did they sell on Saturday? (9) A sloth crawls 2610 cm in an hour. How many meters can it cover in 15 minutes? (10) A cafeteria sells 210.91 liters of lemonade on Tuesday and 18.12 liters more than this quantity on Wednesday. In total, how many liters of lemonade did they sell? (11) What do you get when you subtract 596.94 from 686.63? (12) Write the number five tenths in decimal form. (13) How many pieces do we get when we cut a ribbon of length 16.8 meters into 1.2 meter long pieces? (14) What is the smallest number that should be added to 11.58 to give an even number? (15) A snail crawls 48 cm in 32 minutes. It crawls another 39 cm in 26 minutes. How many metres does it crawl in total?
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Answers ID : cn-6-decimals [3] (1) 2.27 We know that 15.27 is not a prime number. On close observation, we find that the nearest prime number less than 15.27 is 13. Therefore, the smallest number that should be subtracted from 15.27 to make it prime = 15.27-13 = 2.27. (2) The Tenths Place In order to find the place value which is 100000 times smaller than the Ten Thousands place, let us divide 10000 by 100000: 10000 = 0.1 100000 Let us see what is the place of 1 in the number 0.1: Thousands Ones Tenths Hundredths Thousandths Ten thousandths TTH TH H T O. (1/10) (1/100) (1/1000) (1/10000) 0. 1 Legend: TTH - Ten Thousands, TH - Thousands, H - Hundreds, T - Tens, O - Ones. We see that 1 is placed in the Tenths place. Therefore, the place 100000 times smaller than the Ten Thousands place is called the Tenths place.
(3) 15.512 ID : cn-6-decimals [4] In order to multiply the two decimal numbers, let us first find out the position of the decimal point in the final product. Let us first count the number of decimal places in both the multiplicands. The total number of decimal places in the product will be the sum of the number of decimal places in both the multiplicands. In the number 5.6, there is 1 decimal place and in 2.77, there are 2 decimal places. Hence, there will be a total of 3 decimal places in the final product. Step 4 Now, let us multiply the two numbers just like whole numbers, and in the final product, place the decimal point such that there are 3 decimal places (i.e. after 3 places from the right): 2 7 7 x 5 6 1 6 6 2 1 3 8 5 0 1 5 5 1 2 Step 5 Now, put the decimal point after three places from right. Therefore, 2.77 5.6 = 15.512 (4) 7 Ten thousandths Let us draw the place value chart to find where the digit 7 is placed in the given number: 20468597 Lakhs Thousands Ones Tenths Hundredths Thousandths Ten thousandths TL L TTH TH H T O. (1/10) (1/100) (1/1000) (1/10000) 2 0 4 6. 8 5 9 7 Legend: TL - Ten Lakhs, L - Lakhs, TTH - Ten Thousands, TH - Thousands, H - Hundreds, T - Tens, O - Ones. From the above table, we observe that 7 is placed under the Ten thousandths place. Hence, the place value of 7 in 2046.8597 is 7 Ten thousandths.
(5) 30.35 kg ID : cn-6-decimals [5] The number of loads of bricks = 9.5 Total weight of all the loads together = 288.325 kg In order to find the weight of one load, we need to divide the total weight by the number of loads. Step 4 Therefore, the weight of one load is 288.325 9.5 = 30.35 kg. (6) 96.84
(7) 0.32 ID : cn-6-decimals [6] If we look at the figure, we notice that, there are a total of 100 boxes. 15 of 100 represents 0.15. Therefore, 1 of 100 represents = 1 100 = 0.01 The difference of the boxes in the given figures = 39-7 = 32 Hence, 32 of 100 represents = Thus, the result of 32 100 = 0.32 is 0.32. (8) 193.58 liters Quantity of grape juice sold on Thursday = 188.49 liters Quantity of grape juice sold on next day (i.e. Friday) = 188.49 + 16.41 = 204.9 liters Quantity of grape juice sold on the day following Friday, i.e., Saturday = 204.9-11.32 = 193.58 liters Step 4 Hence, 193.58 liters of cranberry juice was sold on Saturday.
(9) 6.525 m. ID : cn-6-decimals [7] Distance covered by the snail by crawling for an hour (60 minutes) = 2610 cm Distance covered in 1 minute = 2610 cm 60 = 2610 60 100 meters Therefore, the distance covered by the snail in 15 minutes = 2610 60 100 = 6.525 m 15 (10) 439.94 Quantity of lemonade sold on Tuesday = 210.91 liters Quantity of lemonade sold on the next day (i.e. Wednesday) = 210.91 + 18.12 = 229.03 liters Total quantity of lemonade sold in two days = 210.91 + 229.03 = 439.94 liters
(11) 89.69 ID : cn-6-decimals [8] Decimals with the same number of decimal places are called Like Decimals. The numbers given here are therefore Like Decimals. We need to subtract 596.94 from 686.63. Therefore, 686.63 must be placed on top and 596.94 below that. The digits of the two numbers must be placed according to their place values. Let us now do the subtraction of the two numbers digit by digit, starting from the hundredths and borrowing if needed: Thousands Hundreds Tens Ones. Tenth Hundredth 6 8 6. 6 3-5 9 6. 9 4 0 8 9. 6 9 Step 4 Hence, when we subtract 596.94 from 686.63, we get 89.69. (12) 0.5 Let us first write the given number name as a fraction: 5 10 Converting the fraction into a decimal number, we get: 5 10 = 0.5
(13) 14 ID : cn-6-decimals [9] Total length of the ribbon = 16.8 meters Length of one piece of the ribbon = 1.2 meters Number of pieces of the ribbon = Total length of the ribbon Length of one piece of the ribbon = 16.8 1.2 = 14 Hence, we get 14 pieces of the ribbon. (14) 0.42 (15) 0.87 m. The total distance (in cm) the snail crawls: 48 cm + 39 cm = 87 cm Now, let us convert the distance 87 cm (centimetres) into meters. We know that: 100 cm = 1 m Therefore, 87 cm = 87 m = 0.87 m 100 Hence, the snail crawls 0.87 m in total.